(7x+3)(2x^2-5x-3)=0

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Solution for (7x+3)(2x^2-5x-3)=0 equation: 


Simplifying
(7x + 3)(2x2 + -5x + -3) = 0

Reorder the terms:
(3 + 7x)(2x2 + -5x + -3) = 0

Reorder the terms:
(3 + 7x)(-3 + -5x + 2x2) = 0

Multiply (3 + 7x) * (-3 + -5x + 2x2)
(3(-3 + -5x + 2x2) + 7x * (-3 + -5x + 2x2)) = 0
((-3 * 3 + -5x * 3 + 2x2 * 3) + 7x * (-3 + -5x + 2x2)) = 0
((-9 + -15x + 6x2) + 7x * (-3 + -5x + 2x2)) = 0
(-9 + -15x + 6x2 + (-3 * 7x + -5x * 7x + 2x2 * 7x)) = 0
(-9 + -15x + 6x2 + (-21x + -35x2 + 14x3)) = 0

Reorder the terms:
(-9 + -15x + -21x + 6x2 + -35x2 + 14x3) = 0

Combine like terms: -15x + -21x = -36x
(-9 + -36x + 6x2 + -35x2 + 14x3) = 0

Combine like terms: 6x2 + -35x2 = -29x2
(-9 + -36x + -29x2 + 14x3) = 0

Solving
-9 + -36x + -29x2 + 14x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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